SQL Reference
ARRAY_HAS_ALL
array_has_all(list1, list2)
Section titled “array_has_all(list1, list2)”- list1: T[]
- list2: T[]
Example
Section titled “Example”SELECT array_has_all([1, 2, 3], [2, 3]);SQL Reference
SELECT array_has_all([1, 2, 3], [2, 3]);