SQL Reference
LIST_HAS_ANY
list_has_any(list1, list2)
Section titled “list_has_any(list1, list2)”- list1: T[]
- list2: T[]
Example
Section titled “Example”SELECT list_has_any([1, 2, 3], [2, 3, 4]);SQL Reference
SELECT list_has_any([1, 2, 3], [2, 3, 4]);